BS1IN ITS Martin Ott BW2

geg:

  • Upstream 1Gb/s
  • Downstream 100MB/s
  • Header-, Trailersumme 700b
  • Dateigröße 2Tib ges:
  • Zeit in ganzen minuten Lsg: 2Tib = 2 * 1024 * 1024 * 1024 * 1024 == 2,199023256×10¹²B 1Gb = 1 000 000 000 B 1 Frame = 1518B 22 Bd = 1518B - 700B 818B 1000000000B / 1518B 658761 frames

In 1Gb/s passen 658761 frames/s 658761 * 818B = 538 866 498 B pro sekunde ODER 585,86MB/s


BW3

geg: 500 MiB, Frameminimum 106B, Upstream 10Mbit/s, 1.518B

ges: übertragungszeit

lsg: 1 Mbit = 1,049 MiB 10Mbit = 10,49 MiB |*50 500Mbit = 524,5 MiB

500 MiB / 1,049 = 476,64442326 Mbit

476,64 Mbit * 125 000 == 59 580 000 B

59 580 000B / 1518B = 39250 Frames

39250 * 106B = 4 160 500B

59 580 000B + 4 160 500B = 63740500B

64 740 500 / 8/ 8 ==